What is [H_3O^+] for a solution whose pH-=2.85?

1 Answer
Mar 26, 2017

Well, first we had better specify what pH is..........

Explanation:

And I assume that 2.85=-log_10[H^+]

And taking antilogs..........

10^(-2.85)=[H^+]

So [H^+]=1.41xx10^-3*mol*L^-1.............

See here for an example...........