Fe^3 + 3HOH => Fe(OH)_3 + H^+ => Acidic Soln
CH_3NH_3^+ + HOH => CH_3NH_3OH + H^+ => Acidic Soln
Neither Li^+ or Cl^- will undergo hydrolysis as reaction with water theoretically yields a strong electrolyte (Stg Base; LiOH & Stg Acid; HCl). Such species prefer to remain 100% ionized and the pH at equivalence point for this salt is exclusively dependent upon the autoionization of HOH => pH = 7 at 25^oC & System is pH neutral.
C_6H_5NH_3^+ NO_2^- => C_6H_5NH_3^+ + NO_2^-; Kb(aniline) = 4.2E-10
NO_2^- + HOH => HNO_2 + OH^-; Ka(nitrous acid) = 4.5E-4
C_6H_5NH_3^+ + HOH => C_6H_5NH_3^+OH^- + H^+ => Acidic Solution
The smaller K-value compound dominates hydrolysis => Soln is Acidic b/c Ka < Kb. This means that the anilinium ion is a reasonably strong conjugate acid producing higher degree of hydrolytic effect than the Nitrite ion which => [H^+] > [OH^-] => pH < 7 (acidic).
NaF => Na^+ + F^_
F^- + HOH => HF + OH^- => Basic Solution
