Question #b80b1

1 Answer

[OH^-] = 3 xx 10^(-12)

Explanation:

Since pH + pOH = 14 for all the aqueous solutions

pOH = 14-pH = 11,5

Since
in first approximation pOH = -log[OH^-]
therefore [OH^-] = 10^(-pOH) = 10^(-11,5) = 3 xx 10^(-12)