Question #231e7

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Answer 1 · 2017-08-03T02:51:43

$["H"_3"O"^+] = 1.1xx10^-13$ $M$

We're asked to find the hydronium ion concentration $["H"_3"O"^+]$ , given the hydroxide ion concentration $["OH"^(-)]$ .

At $25$ $""^"o""C"$ , we have the relationship

$ul(K_w = ["OH"^(-)]["H"_3"O"^+] = 1.00xx10^-14color(white)(l)M^2$

Since $["OH"^- ]$ is given as

$9.0xx10^-2$ $M$

we plug that into the equation and solve for $["H"_3"O"^+]$ :

$["H"_3"O"^+] = (1.00xx10^-14color(white)(l)M^2)/(9.0xx10^-2color(white)(l)M) = color(red)(ulbar(|stackrel(" ")(" "1.1xx10^-13color(white)(l)M" ")|)$