Question #f1da9

1 Answer
Aug 3, 2017

["OH"^- ] = 6.3xx10^-13 M

Explanation:

We're asked to find the hydroxide ion concentration ["OH"^(-)], given the hydronium ion concentration ["H"_3"O"^+].

At 25 ""^"o""C", we have the relationship

ul(K_w = ["OH"^(-)]["H"_3"O"^+] = 1.00xx10^-14color(white)(l)M^2

Since ["H"_3"O"^+] is given as

1.6xx10^-2 M

we plug that into the equation and solve for ["OH"^(-)]:

["OH"^(-)] = (1.00xx10^-14color(white)(l)M^2)/(1.6xx10^-2color(white)(l)M) = color(red)(ulbar(|stackrel(" ")(" "6.3xx10^-13color(white)(l)M" ")|)

rounded to 2 significant figures.