How do I solve $4(x-3)-(x-5)=0$ ?

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Answer 1 · 2017-08-14T20:51:06

$x=7/3$

Refer to the explanation for the process.

Solve:

$4(x-3)-(x-5)=0$

Expand.

$4x-12-x+5=0$

Simplify.

$3x-7=0$

Add $7$ to both sides.

$3x=7$

Divide both sides by $3$ .

$x=7/3$

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