Question #3dd5d

1 Answer
Michael
Aug 31, 2017

sf(pH=3)

Explanation:

The acid dissociates:

sf(HZrightleftharpoonsH^++Z^-)

Since it is 1% ionised then sf([H^+]=0.10xx0.01=0.001color(white)(x)"mol/l")

sf(pH=-log[H^+]=-log(10^(-3))=3)

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