Question

How do I evaluate the indefinite integral `intsec^2(x)*tan(x)dx` ?

Answer 1

The answer is `=1/2sec^2x+C`

Explanation:

Perform this integral by substitution

Let `u=sec^2x`, `=>`, `du=2sec^2xtanxdx`

Therefore, the integral is

`I=intsec^2xtanxdx=1/2intdu`

`=1/2u`

`=1/2sec^2x+C`