How do I evaluate the indefinite integral $intsec^2(x)*tan(x)dx$ ?

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Answer 1 · 2018-06-08T12:20:21

The answer is $=1/2sec^2x+C$

Perform this integral by substitution

Let $u=sec^2x$ , $=>$ , $du=2sec^2xtanxdx$

Therefore, the integral is

$I=intsec^2xtanxdx=1/2intdu$

$=1/2u$

$=1/2sec^2x+C$

How do I evaluate the indefinite integral intsec^2(x)*tan(x)dxintsec^2(x)*tan(x)dx ?