Question

How do I find the integral of `f(x)=cot^5xcsc^2x`?

Answer 1

Use `u`-substitution: Let `u=cotx`. This makes `du=-csc^2x dx` and the integral becomes:

`int cot^5xcsc^2x dx = - int u^5 du = -u^6/6+C`

`=-1/6 cot^6x +C`