How do I find the integral of $f(x)=cot^5xcsc^2x$ ?

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Answer 1 · 2015-03-22T19:14:44

Use $u$ -substitution: Let $u=cotx$ . This makes $du=-csc^2x dx$ and the integral becomes:

$int cot^5xcsc^2x dx = - int u^5 du = -u^6/6+C$

$=-1/6 cot^6x +C$

How do I find the integral of f(x)=cot^5xcsc^2xf(x)=cot^5xcsc^2x?