How do you differentiate $cos^2x/(1 - sin ^2x)$ ?

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Answer 1 · 2018-03-08T16:04:08

Rewrite and find that the derivative is $0$

Since $1-sin^2x = cos^2x$ , we have

$cos^2x/(1-sin^2x) = cos^2x/cos^2x = 1$ .

So the derivative is $0$

How do you differentiate cos^2x/(1 - sin ^2x)cos^2x/(1 - sin ^2x)?