How do you differentiate $f(x)=sec(5x)$ ?

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Answer 1 · 2017-02-28T20:54:58

See below

This is a result you should learn:

$d/dxsecf(x)=secf(x)tanf(x)f'(x)$

$d/dxsec5x=5sec5xtan5x$

How do you differentiate f(x)=sec(5x)f(x)=sec(5x)?