How do you differentiate #f(x)=tan(3x)-cot(3x)#? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Sonnhard Jun 22, 2018 #f'(x)=3/(sin^2(3x)*cos^2(3x))# Explanation: Note that #(tan(x))'=1/cos^2(x)# and #(cot(x))'=-1/sin^2(x)# then we get #f'(x)=3/cos^2(3x)+3/sin^2(3x)# Answer link Related questions What is Derivatives of #y=sec(x)# ? What is the Derivative of #y=sec(x^2)#? What is the Derivative of #y=x sec(kx)#? What is the Derivative of #y=sec ^ 2(x)#? What is the derivative of #y=4 sec ^2(x)#? What is the derivative of #y=ln(sec(x)+tan(x))#? What is the derivative of #y=sec^2(x)#? What is the derivative of #y=sec^2(x) + tan^2(x)#? What is the derivative of #y=sec^3(x)#? What is the derivative of #y=sec(x) tan(x)#? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 3182 views around the world You can reuse this answer Creative Commons License