How do you differentiate $f(x)=tan(3x)-cot(3x)$ ?

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Answer 1 · 2018-06-22T09:43:30

$f'(x)=3/(sin^2(3x)*cos^2(3x))$

Note that

$(tan(x))'=1/cos^2(x)$
and

$(cot(x))'=-1/sin^2(x)$
then we get
$f'(x)=3/cos^2(3x)+3/sin^2(3x)$

How do you differentiate f(x)=tan(3x)-cot(3x)f(x)=tan(3x)-cot(3x)?