How do you differentiate $g(x) =cscx -x secx$ ?

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Answer 1 · 2016-04-13T19:44:12

$g'(x)=-cscxcotx-xsecxtanx-secx$

$g'(x)=-cscxcotx-[xsecxtanx+secx]->$ product rule
$g'(x)=-cscxcotx-xsecxtanx-secx$

How do you differentiate g(x) =cscx -x secx g(x) =cscx -x secx ?