How do you differentiate $g(x) =sin^2(x/6)$ ?

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Answer 1 · 2016-03-31T07:11:59

$(dg)/(dx)=1/6sin(x/3)$

To differentiate $g(x)=sin^2(x/6)$ , we use the concept of function of function, as $g(x)=(f(x))^2$ where $f(x)=sin(x/6)$ .

Hence, $(dg)/(dx)=(dg)/(df)*(df)/(dx)$

= $2sin(x/6)*cos(x/6)*1/6$

= $1/6sin(x/3)$ (using formula $sin2x=2sinxcosx$ )

How do you differentiate g(x) =sin^2(x/6) g(x) =sin^2(x/6) ?