What is the derivative of $tan(2x)$ ?

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Answer 1 · 2016-10-26T15:50:35

$(dy)/(dx)=2sec^2(2x)$

$y=tan(2x)$

$u=2x=>(du)/dx=2$

$y=tanu=>(dy)/(du)=sec^2u$

$(dy)/(dx)=(dy)/(du)xx(du)/(dx)$

$:.(dy)/(dx)=(sec^2u)xx2$

$(dy)/(dx)=2sec^2u=2sec^2(2x)$

What is the derivative of tan(2x)tan(2x)?