How do you differentiate the following parametric equation: # x(t)=lnt, y(t)=(t-3) #?
1 Answer
May 23, 2016
Explanation:
The derivative
#dy/dx# of parametric equations is.
#color(red)(|bar(ul(color(white)(a/a)color(black)(dy/dx=(dy/dt)/(dx/dt))color(white)(a/a)|)))# here x = lnt
#rArrdx/dt=1/t# and
#y=t-3rArrdy/dt=1#
#rArrdy/dx=1/(1/t)=1xxt/1=t#
