How do you differentiate the following parametric equation: $x (t) = ln t, y (t) = (t - 3)$ $x(t)=lnt, y(t)=(t-3)$ ?

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How do you differentiate the following parametric equation: $x (t) = ln t, y (t) = (t - 3)$ $x(t)=lnt, y(t)=(t-3)$ ?

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Answer 1 · 2016-05-23T10:02:37

$\frac{d y}{d x} = t$ $dy/dx=t$

Explanation:

The derivative $\frac{d y}{d x}$ $dy/dx$ of parametric equations is.

$color(red)(|bar(ul(color(white)(a/a)color(black)(dy/dx=(dy/dt)/(dx/dt))color(white)(a/a)|)))$

here x = lnt $rArrdx/dt=1/t$

and $y=t-3rArrdy/dt=1$

$rArrdy/dx=1/(1/t)=1xxt/1=t$

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How do you differentiate the following parametric equation: $x (t) = ln t, y (t) = (t - 3)$ $x(t)=lnt, y(t)=(t-3)$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you differentiate the following parametric equation: x(t)=lnt, y(t)=(t-3) x(t)=lnt,y(t)=(t−3) x(t)=lnt, y(t)=(t-3) ?

1 Answer

Explanation:

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Impact of this question

How do you differentiate the following parametric equation: $x (t) = ln t, y (t) = (t - 3)$ $x(t)=lnt, y(t)=(t-3)$ ?