Question

How do you differentiate the following parametric equation: `x(t)=lnt, y(t)=(t-3)`?

Answer 1

`dy/dx=t`

Explanation:

The derivative `dy/dx`of parametric equations is.

`color(red)(|bar(ul(color(white)(a/a)color(black)(dy/dx=(dy/dt)/(dx/dt))color(white)(a/a)|)))`

here x = lnt `rArrdx/dt=1/t`

and `y=t-3rArrdy/dt=1`

`rArrdy/dx=1/(1/t)=1xxt/1=t`