Question

How do you differentiate the following parametric equation: `x(t)=t^3-5t, y(t)=(t-3)`?

Answer 1

`dy/dx = 1/(3t^2 - 5 )`

Explanation:

`x = t^3 - 5t rArr dx/dt = 3t^2 - 5`

and `y = t - 3 rArr dy/dt = 1`

`dy/dx = dy/dt xx dt/dx`

note that: `dt/dx =( 1)/(dx/dt)`

`rArr dy/dx = 1/(3t^2 - 5 )`