How do you differentiate the following parametric equation: # x(t)=t^3-5t, y(t)=(t-3) #?
1 Answer
Jan 13, 2016
Explanation:
# x = t^3 - 5t rArr dx/dt = 3t^2 - 5 # and
# y = t - 3 rArr dy/dt = 1 #
#dy/dx = dy/dt xx dt/dx # note that:
# dt/dx =( 1)/(dx/dt) #
#rArr dy/dx = 1/(3t^2 - 5 ) #
