How do you differentiate $y=(8x+sec(x))^7$ ?

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Answer 1 · 2015-07-07T14:08:53

$y'=7(8x+secx)^(6).(8+secxtanx)$

$y=(8x+secx)^7$

Using the chain rule:

$y'=7(8x+secx)^(6).(8+secxtanx)$

How do you differentiate y=(8x+sec(x))^7y=(8x+sec(x))^7?