How do you differentiate $y = tan(x + sec x)$ ?

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Answer 1 · 2015-05-06T16:39:58

Use the Chain Rule, together with the derivatives of tangent and secant.

$y = tan(x + sec x)$

$dy/dx = sec^2(x+secx) [d/dx(x+secx)]$

$color(white)"sss"$ $= sec^2(x+secx) [1+secxtanx]$

You could write the answer:

$dy/dx = (1+secxtanx)sec^2(x+secx)$

How do you differentiate y = tan(x + sec x)y = tan(x + sec x)?