How do you divide (2sqrt(3))/(2sqrt(5)) and sqrt(5)/sqrt(10)?

1 Answer
Mar 22, 2015

Ok, by divide, I presume you are talking about rationalising the denominator.

For info on how to do this, check this site out: http://www.purplemath.com/modules/radicals5.htm

Ok, on to solving:

In the first one, notice how the problem can be rewritten as: (2*sqrt(3))/(2*sqrt(5)). This can be rewritten as (2/2)*(sqrt(3)/(sqrt(5))). Since 2/2 is just 1, we can rewrite the problem as

(1)*(sqrt(3)/(sqrt(5))), which is just (sqrt(3)/(sqrt(5))).

From here, we rationalise the denominator by multiplying the expression by sqrt(5)/sqrt(5). We can do this because sqrt(5)/sqrt(5) is simply 1, and multiplying something by 1 doesn't change the nature of the expression.

So our expression becomes: sqrt(3)/(sqrt(5))*sqrt(5)/sqrt(5), which simplifies to become sqrt(15)/5. Since sqrt(15) is not something we can simplify, our final answer remains sqrt(15)/5.

Now for the second problem, the procedure is basically the same.

We multiply the expression by sqrt(10)/sqrt(10), so we get: sqrt(5)/sqrt(10)*sqrt(10)/sqrt(10), which simplifies to become sqrt(50)/sqrt(100).

Since sqrt(100) simplifies to 10, the expression can be simplified to read: sqrt(50)/10.

Now unlike the last problem, this numerator can be simplified, as it is a multiple of 25. sqrt(50)=5sqrt(2)

So our expression reads (5sqrt(2))/10, which can be simplified to sqrt(2)/2 for our final answer.