How do you divide (3sqrt(2x^6y))/(5 sqrt(8x^5 y^6))3√2x6y5√8x5y6? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Joe D. Apr 3, 2015 (3sqrt(2x^6y))/(5sqrt(8x^5y^6))3√2x6y5√8x5y6 = 3/5 * sqrt((2x^6y)/(8x^5y^6))=35⋅√2x6y8x5y6 = 3/5 * sqrt(1/4 * xy^(-5))=35⋅√14⋅xy−5 = 3/5 * sqrt((1/2)^2 * xy^(-5))=35⋅√(12)2⋅xy−5 =3/5*1/2*sqrt(xy^(-5))=35⋅12⋅√xy−5 =3/10sqrt(xy^(-5))=310√xy−5 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}2√3? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)73√5? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))(√a+√b)(√a−√b)? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}2x√5x? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)√5√15? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))(7√13+2√6)(2√3+3√6)? See all questions in Multiplication and Division of Radicals Impact of this question 1858 views around the world You can reuse this answer Creative Commons License