How do you divide $\frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ $(sqrt3 - 1)/(sqrt3+1)$ ?

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Answer 1 · 2015-04-05T01:37:30

Try rationalizing by multiplying and dividing by $\sqrt{3} - 1$ $sqrt(3)-1$ :
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Answer 2 · 2015-04-05T01:38:14

Multiply the numerator and denominator by the conjugate of the denominator to clear the radical from the denominator, then simplify.

$\frac{\sqrt{3} - 1}{\sqrt{3} + 1} \cdot \frac{\sqrt{3} - 1}{\sqrt{3} - 1}$ $(sqrt(3)-1)/(sqrt(3)+1)*(sqrt(3)-1)/(sqrt(3)-1)$

$= \frac{3 - 2 \sqrt{3} + 1}{3 - 1}$ $= (3-2sqrt(3)+1)/(3-1)$

$= 2 - \sqrt{3}$ $=2-sqrt(3)$

How do you divide √3−1√3+1(sqrt3 - 1)/(sqrt3+1)?