How do you evaluate $(-32)^(2/5)$ ?

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Answer 1 · 2015-06-13T02:17:44

You can rewrite, remembering that fractional powers are roots

$=root 5 ((-32)^2)$

We first do the square:

$=root 5 1024$

You may know that $1024=2^10$ and then:

$=root 5 (2^10)=2^(10/5)=2^2=4$

How do you evaluate (-32)^(2/5)(-32)^(2/5)?