How do you evaluate the integral $\int \frac{d x}{e^{3 x}}$ $int dx/e^(3x)$ ?

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Answer 1 · 2017-01-12T08:02:24

$= - \frac{1}{3} e^{- 3 x} + c$ $=-1/3e^(-3x)+c$

You can rewrite the expression as:

$- \frac{1}{3} \int - 3 e^{- 3 x} d x$ $-1/3int-3e^(-3x)dx$

Then you can get:

$= - \frac{1}{3} e^{- 3 x} + c$ $=-1/3e^(-3x)+c$

How do you evaluate the integral ∫dxe3xint dx/e^(3x)?