How do you evaluate the integral $int e^(1/x)/x^2$ ?

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Answer 1 · 2017-01-28T11:35:04

$int e^(1/x)/x^2dx = -e^(1/x) + C$

Substitute: $t=1/x$ , $dt = -1/x^2dx$

so we have:

$int e^(1/x)/x^2dx = -int e^tdt = -e^t + C$

and undoing the substitution:

$int e^(1/x)/x^2dx = -e^(1/x) + C$

How do you evaluate the integral int e^(1/x)/x^2int e^(1/x)/x^2?