How do you express 1x3+4x in partial fractions?

1 Answer
Mar 5, 2016

let
1x3+4x=1x(x2+4)=ax+bxx2+4=a(x2+4)+bx2x(x2+4)
Now
1=(a(x2+4)+bx2)
putting x=0 in the above identity we have 4a=1a=14
Again putting x=1, we have 5a+b=1
putting a=14 in the 2nd equation 5a+b=1
we get 54+b=1b=14

Hence we can write
1x3+4x=14(1xxx2+4)