How do you express $(-2x-3)/(x^2-x)$ in partial fractions?

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Answer 1 · 2016-02-20T09:53:58

$3/x-5/(x-1)$

To write algebraic expression $(−2x−3)/(x^2−x)$ ,

we first factorize $(x^2−x)$ i.e. $x(x−1)$ .

Hence partial fractions will be of he type

$A/x+B/(x-1)$ or $(Ax-A+Bx)/(x(x-1))$ or

$((A+B)x-A)/(x(x-1))$

Hence $A+B=-2$

and $-A=-3$ i.e. $A=3$ and $B=-5$

Hence partial fractions are

$3/x-5/(x-1)$

How do you express (-2x-3)/(x^2-x) (-2x-3)/(x^2-x) in partial fractions?