How do you express 3/((1 + x)(1 - 2x)) in partial fractions? Precalculus Matrix Row Operations Partial Fraction Decomposition (Linear Denominators) 1 Answer Bdub Mar 21, 2016 3/((1+x)(1-2x)) = 1/(1+x) +2/(1-2x) Explanation: 3/((1+x)(1-2x)) = A/(1+x) +B/(1-2x) 3=A(1-2x)+B((1+x) 3=A-2Ax+B+Bx A+B=3, -2A+B=0 B=3-A->-2A+3-A=0->-3A+3=0 -3A=-3,A=1,B=2 3/((1+x)(1-2x)) = 1/(1+x) +2/(1-2x) Answer link Related questions What does partial-fraction decomposition mean? What is the partial-fraction decomposition of (5x+7)/(x^2+4x-5)? What is the partial-fraction decomposition of (x+11)/((x+3)(x-5))? What is the partial-fraction decomposition of (x^2+2x+7)/(x(x-1)^2)? How do you write 2/(x^3-x^2) as a partial fraction decomposition? How do you write x^4/(x-1)^3 as a partial fraction decomposition? How do you write (3x)/((x + 2)(x - 1)) as a partial fraction decomposition? How do you write the partial fraction decomposition of the rational expression x^2/ (x^2+x+4)? How do you write the partial fraction decomposition of the rational expression # (3x^2 + 12x -... How do you write the partial fraction decomposition of the rational expression 1/((x+6)(x^2+3))? See all questions in Partial Fraction Decomposition (Linear Denominators) Impact of this question 1392 views around the world You can reuse this answer Creative Commons License