How do you express $\frac{6 x + 5}{{(x + 2)}^{4}}$ $(6x+5) / (x+2) ^4$ in partial fractions?

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How do you express $\frac{6 x + 5}{{(x + 2)}^{4}}$ $(6x+5) / (x+2) ^4$ in partial fractions?

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Answer 1 · 2016-08-07T20:55:53

$\frac{6 x + 5}{{(x + 2)}^{4}} = \frac{6}{{(x + 2)}^{3}} - \frac{7}{{(x + 2)}^{4}}$ $(6x+5)/(x+2)^4=6/(x+2)^3-7/(x+2)^4$

Explanation:

$\frac{6 x + 5}{{(x + 2)}^{4}}$ $(6x+5)/(x+2)^4$

$= \frac{6 x + 12 - 7}{{(x + 2)}^{4}}$ $=(6x+12-7)/(x+2)^4$

$= \frac{6 (x + 2) - 7}{{(x + 2)}^{4}}$ $=(6(x+2)-7)/(x+2)^4$

$= \frac{6}{{(x + 2)}^{3}} - \frac{7}{{(x + 2)}^{4}}$ $=6/(x+2)^3-7/(x+2)^4$

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How do you express $\frac{6 x + 5}{{(x + 2)}^{4}}$ $(6x+5) / (x+2) ^4$ in partial fractions?

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