How do you express #(6x+5) / (x+2) ^4# in partial fractions?
1 Answer
Aug 7, 2016
#(6x+5)/(x+2)^4=6/(x+2)^3-7/(x+2)^4#
Explanation:
#(6x+5)/(x+2)^4#
#=(6x+12-7)/(x+2)^4#
#=(6(x+2)-7)/(x+2)^4#
#=6/(x+2)^3-7/(x+2)^4#
