How do you express x3+1x2+3 in partial fractions?

1 Answer
Sep 17, 2016

x3+1x2+3=x3x1x2+3

Explanation:

Note that x2+33>0 for any Real values of x, so the denominator has no Real zeros and we cannot break it down into linear factors (assuming that we want to stay with Real coefficients).

So the form of solution we are looking for is: p(x)+Ax+Bx2+3 for some polynomial p(x) and constants A,B...

x3+1x2+3=(x3+3x)(3x1)x2+3=x3x1x2+3