How do you find lim (1-2t^-1+t^-2)/(3-4t^-1) as t->0? Calculus Limits Limits at Infinity and Horizontal Asymptotes 1 Answer Guillaume L. May 10, 2018 Lim_"t->0"(1-2t^-1+t^-2)/(3-4t^-1)=±oo depending on if t->+oo or t->-oo Explanation: Lim_"t->0"(1-2t^-1+t^-2)/(3-4t^-1) =Lim_"t->0"(t²-2t+1)/(3t²-4t) =Lim_"t->0"-1/(4t) =±oo depending on if t->+oo or t->-oo \0/ here's our answer! Answer link Related questions What kind of functions have horizontal asymptotes? How do you find horizontal asymptotes for f(x) = arctan(x) ? How do you find the horizontal asymptote of a curve? How do you find the horizontal asymptote of the graph of y=(-2x^6+5x+8)/(8x^6+6x+5) ? How do you find the horizontal asymptote of the graph of y=(-4x^6+6x+3)/(8x^6+9x+3) ? How do you find the horizontal asymptote of the graph of y=3x^6-7x+10/8x^5+9x+10? How do you find the horizontal asymptote of the graph of y=6x^2 ? How can i find horizontal asymptote? How do you find horizontal asymptotes using limits? What are all horizontal asymptotes of the graph y=(5+2^x)/(1-2^x) ? See all questions in Limits at Infinity and Horizontal Asymptotes Impact of this question 1568 views around the world You can reuse this answer Creative Commons License