How do you find $lim (3x)/(4x-10)$ as $x->-oo$ ?

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Answer 1 · 2017-02-16T17:48:55

$-3/4$

Ignore the -10 since it's irrelevant when you get to high numbers such as infinity so treat the limit as:

$lim (3x)/(4x)$ as x→−∞

Cancel out the x's:

$lim (3)/(4)$ as x→−∞

Now there are no more x's so $3/4$ is your answer.

How do you find lim (3x)/(4x-10)lim (3x)/(4x-10) as x->-oox->-oo?