Question

How do you find `lim cost/t^2` as `t->oo`?

Answer 1

`0`

Explanation:

`cost` oscillates between the values of `-1` and `1`.

The denominator, `t^2`, approaches `oo` as `trarroo`.

It's fairly simple to see that no matter what the value of `cost` is, it will be significantly "overpowered" by the growth of `t^2` in the denominator.

As `t` gets sufficiently large, we will have very large values in the denominator and only value between `-1` and `1` in the numerator.

Thus, we get values like `1/10000` and `-1/100000000` as `t` increases. These terms get closer and closer to being `0`.

So:

`lim_(trarroo)cost/t^2=0`