How do you find $lim (x^2-x+4)/(3x^2+2x-3)$ as $x->oo$ ?

Question

1574 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-19T17:49:31

$1/3$

Divide numerator and the denominator by $x^2$ . Accordingly, it is $(1-1/x +4/x^2)/(3+2/x -3/x^2)$ . Now applying the limit $x-> oo$ , it becomes

= $1/3$

How do you find lim (x^2-x+4)/(3x^2+2x-3)lim (x^2-x+4)/(3x^2+2x-3) as x->oox->oo?