How do you find lim x-sqrtx as x->oo? Calculus Limits Limits at Infinity and Horizontal Asymptotes 1 Answer Andrea S. Feb 4, 2017 lim_(x->oo) (x-sqrt(x)) = +oo Explanation: Write the function as: f(x) = x-sqrt(x) = sqrt(x) (sqrt(x) -1) As: lim_(x->oo) sqrt(x) = +oo and lim_(x->oo) sqrt(x)-1 = +oo then also: lim_(x->oo) sqrt(x)(sqrt(x)-1) = +oo Answer link Related questions What kind of functions have horizontal asymptotes? How do you find horizontal asymptotes for f(x) = arctan(x) ? How do you find the horizontal asymptote of a curve? How do you find the horizontal asymptote of the graph of y=(-2x^6+5x+8)/(8x^6+6x+5) ? How do you find the horizontal asymptote of the graph of y=(-4x^6+6x+3)/(8x^6+9x+3) ? How do you find the horizontal asymptote of the graph of y=3x^6-7x+10/8x^5+9x+10? How do you find the horizontal asymptote of the graph of y=6x^2 ? How can i find horizontal asymptote? How do you find horizontal asymptotes using limits? What are all horizontal asymptotes of the graph y=(5+2^x)/(1-2^x) ? See all questions in Limits at Infinity and Horizontal Asymptotes Impact of this question 1718 views around the world You can reuse this answer Creative Commons License