How do you find the limit #lim_(x->5)(x^2-6x+5)/(x^2-25)# ?
1 Answer
Jul 29, 2014
#=2/5#
Explanation
#=lim_(x->5)(x^2-6x+5)/(x^2-25)# , if we plug#x=5# , we get#0/0# formUsing Finding Limits Algebraically,
#=lim_(x->5)(x^2-5x-x+5)/((x+5)(x-5))#
#=lim_(x->5)(x(x-5)-1(x-5))/((x+5)(x-5))#
#=lim_(x->5)((x-5)(x-1))/((x+5)(x-5))#
#=lim_(x->5)((x-1))/((x+5))#
#=(5-1)/(5+5)#
#=4/10# #=2/5#
