How do you find the limit #lim_(x->-4)(x^2+5x+4)/(x^2+3x-4)# ?
1 Answer
Jul 29, 2014
#=3/5# Explanation,
Using Finding Limits Algebraically,
#=lim_(x->-4)(x^2+5x+4)/(x^2+3x-4)# , if we plug#x=-4# , we get#0/0# form
#=lim_(x->-4)(x^2+4x+x+4)/(x^2+4x-x-4)#
#=lim_(x->-4)(x(x+4)+1(x+4))/(x(x+4)-1(x+4))#
#=lim_(x->-4)((x+4)(x+1))/((x+4)(x-1))#
#=lim_(x->-4)((x+1))/((x-1))#
#=(-3)/-5#
#=3/5#
