How do you find the antiderivative of $1/((x^2+25)^2) dx$ ?

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Answer 1 · 2015-09-13T03:11:38

$dy/dx =( -4x)/(x^2+25)^(-3)$

In order to have a simple solution, the above expression can be written as

$y = (x^2+25)^(-2)$

Now use function of a function rule

$dy/dx = -2(x^2+25)^(-3)(2x)$
$dy/dx = -4x(x^2+25)^(-3)$
$dy/dx =( -4x)/(x^2+25)^(-3)$

You can use the quotient rule also

Look at this

How do you find the antiderivative of 1/((x^2+25)^2) dx1/((x^2+25)^2) dx?