How do you find the antiderivative of $e^{3 x}$ $e^(3x)$ ?

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Answer 1 · 2016-12-24T16:01:19

$int e^(3x) \ dx = 1/3e^(3x) + C$

Using $d/dx e^(ax) = ae^(ax) <=> int ae^(ax) \ dx = e^(ax) + C'$

$:. \ int e^(ax) \ dx = e^(ax)/a + C$

Hence, $int e^(3x) \ dx = 1/3e^(3x) + C$

How do you find the antiderivative of e^(3x)e3xe^(3x)?