How do you find the area of a triangle ABC, if a = 23, b = 46 , and c = 41?

1 Answer
Mar 12, 2018

Area of the triangle is 470.914 sq.unit.

Explanation:

In triangle DeltaABC ; a= 23 , b=46 , c=41

The semi perimeter of triangle is s=(a+b+c)/2 or

s= (23+46+41)/2 =55 unit

Area of the triangle is A_t=sqrt(s(s-a)(s-b)(s-c) or

A_t=sqrt(55(55-23)(55-46)(55-41) or

A_t=sqrt(55*32*9*14)=sqrt(221760)~~470.914 sq.unit

Area of the triangle is 470.914 sq.unit. [Ans]