How do you find the area of a triangleGHI, if $angleI = 15^@$ , $g = 14.2$ , and $h = 7.9$ ?

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Answer 1 · 2014-11-06T23:09:05

The height $k$ of Triangle GHI with HI as its base can be found by

$"(Height)"=7.9sin(15^circ)$

The area $A$ of Triangle GHI can be found by

$A=1/2"(Base)(Height)"=1/2cdot 14.2 cdot 7.9 sin(15^circ) approx 14.52$

I hope that this was helpful.

How do you find the area of a triangleGHI, if angleI = 15^@angleI = 15^@, g = 14.2g = 14.2 , and h = 7.9h = 7.9?