How do you find the derivative of $y=tan^2(3x)$ ?

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Answer 1 · 2014-09-08T17:37:26

By using the Chain Rule twice,

$y'=6tan(3x)sec^2(3x)$

Let us look at some details.
By Chain Rule,

$y'=2tan(3x)cdot(tan(3x))'$

by another application of Chain Rule to $(tan(3x))'$ ,

$=2tan(3x)cdot sec^2(3x)cdot3$

by cleaning up a bit,

$=6tan(3x)sec^2(3x)$

How do you find the derivative of y=tan^2(3x)y=tan^2(3x)?