How do you find the derivative of $y=tan(3x)$ ?

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Answer 1 · 2018-04-14T16:05:32

$(dy)/(dx)=3sec^2 3x$

we use teh chain rule

$(dy)/(dx)=color(red)((dy)/(du))(du)/(dx)$

$y=tan3x$

$u=3x=>(du)/(dx)=3$

$:color(red)(y=tanu=>(dy)/(du)=sec^2u)$

$(dy)/(dx)=color(red)(sec^2u)xx3$

$(dy)/(dx)=3sec^2u=3sec^2 3x$

How do you find the derivative of y=tan(3x)y=tan(3x)?