How do you find the following product ${(4 x y + y)}^{2}$ $(4xy + y)^2$ ?

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Answer 1 · 2016-10-24T15:53:23

$= 16 x^{2} y^{2} + 8 x y^{2} + y^{2}$ $=16x^2y^2+8xy^2+y^2$

To expand the given squared sum polynomial we will apply this polynomial identity

${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $color(red)((a+b)^2=a^2+2ab+b^2)$

${(4 x y + y)}^{2}$ $(4xy+y) ^2$
$= {(4 x y)}^{2} + 2 (4 x y) y + y^{2}$ $=color(red)((4xy)^2+2(4xy)y+y^2)$

$= 16 x^{2} y^{2} + 8 x y^{2} + y^{2}$ $=16x^2y^2+8xy^2+y^2$

How do you find the following product (4xy + y)^2(4xy+y)2(4xy + y)^2?