How do you find the integral of $e^{(- \frac{1}{2}) \cdot x}$ $e^((-1/2)*x)$ ?

Question

How do you find the integral of $e^{(- \frac{1}{2}) \cdot x}$ $e^((-1/2)*x)$ ?

1 Answer

Impact of this question

15893 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-26T15:05:10

$- 2 e^{- \frac{1}{2} x} + C$ $-2e^(-1/2x)+C$

Explanation:

$t = - \frac{1}{2} x \Rightarrow d t = - \frac{1}{2} d x \Rightarrow d x = - 2 d t$ $t=-1/2x => dt=-1/2dx => dx=-2dt$

$I = \int e^{- \frac{1}{2} x} d x = \int e^{t} \cdot (- 2 d t) = - 2 \int e^{t} d t = - 2 e^{t} + C$ $I=int e^(-1/2x)dx = int e^t*(-2dt) = -2 inte^tdt = -2e^t + C$

$I = - 2 e^{- \frac{1}{2} x} + C$ $I=-2e^(-1/2x)+C$

Science

Math

Humanities

... and beyond

How do you find the integral of $e^{(- \frac{1}{2}) \cdot x}$ $e^((-1/2)*x)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the integral of e(−12)⋅xe^((-1/2)*x)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the integral of $e^{(- \frac{1}{2}) \cdot x}$ $e^((-1/2)*x)$ ?