How do you find the intercepts for $y=1/4x + 3$ ?

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Answer 1 · 2015-06-19T19:40:56

Y-intercept: $x=0, y=3$ ;
X-intercept: $x=-12, y=0$

You have to set:
$x=0$ in your equation so you get: $y=3$ ;
and then set $y=0$ to get: $x=-12$ .

How do you find the intercepts for y=1/4x + 3y=1/4x + 3?