Question

How do you find the intercepts for `y=-3x+3`?

Answer 1

The intercept with the `y` axis is where `x=0`, hence `y = -3*0 + 3 = 3`. That is `(0, 3)`

The intercept with the `x` axis is where `y=0`, hence `0 = -3x + 3`, hence `x = 1`. That is `(1, 0)`

Explanation:

To find where `y = -3x + 3` intercepts the `y` axis, substitute `x=0` into the equation to find:

`y = (-3*0) + 3 = 0 + 3 = 3`.

That is `(0, 3)`

To find where `y = -3x + 3` intercepts the `x` axis, substitute `y=0` into the equation to find:

`0 = -3x+3`

Add #3x to both sides to get:

`3x=3`

Divide both sides by `3` to get:

`x = 1`.

That is `(1, 0)`

graph{-3x+3 [-9.5, 10.5, -3, 7]}