How do you find the intercepts of $5x - 3y = 15$ ?

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Answer 1 · 2016-03-24T15:49:58

3 and 5

putting $x=0$ we get y - intercept ie. $5xx0-3y=15=>y=-5$
putting $y=0$ we get x - intercept ie. $5x-3xx0=15=>x=3$

How do you find the intercepts of 5x - 3y = 155x - 3y = 15?