How do you find the product $(2 m + 3) (2 m - 3) (m + 4)$ $(2m+3)(2m-3)(m+4)$ ?

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Answer 1 · 2017-06-22T03:37:57

$4 m^{3} - 16 m^{2} - 9 m - 36$ $4m^3-16m^2-9m-36$

$(2 m + 3) (2 m - 3)$ $(2m+3)(2m-3)$ is a difference of squares so you can either F.O.I.L. or use difference of squares $= (4 m^{2} - 9)$ $=(4m^2-9)$

next multiply by the remaining factor $(m + 4)$ $(m+4)$

$(4 m^{2} - 9) (m + 4)$ $(4m^2-9)(m+4)$ foiled equals $4 m^{3} - 16 m^{2} - 9 m - 36$ $4m^3-16m^2-9m-36$

How do you find the product (2m+3)(2m-3)(m+4)(2m+3)(2m−3)(m+4)(2m+3)(2m-3)(m+4)?