How do you find the product ${(2 x - 5)}^{2}$ $(2x-5)^2$ ?

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Answer 1 · 2017-06-07T20:45:00

See a solution process below:

This is a special form of a quadratic which uses the formula:

${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ $(a - b)^2 = a^2 - 2ab + b^2$

Substituting $2 x$ $2x$ for $a$ $a$ and $5$ $5$ for $b$ $b$ gives:

${(2 x - 5)}^{2} = {(2 x)}^{2} - 2 (2 x) 5 + 5^{2} =$ $(2x - 5)^2 = (2x)^2 - 2(2x)5 + 5^2 =$

$4 x^{2} - 20 x + 25$ $4x^2 - 20x + 25$

How do you find the product (2x-5)^2(2x−5)2(2x-5)^2?